Question

Determine the ratio in which the line segment 3x+y-9=0divides the line segment joining the

points (1, 3) and (2, 7)​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

Ratio is 3:4.

Step-by-step explanation:

Let ratio be k:1.

By using section formula,

$(x,y) = ( \frac{mx2 + nx1}{m + n} ,\frac{my2 + ny1}{m + n}) \\ \\ (x,y) = ( \frac{2k + 1}{k + 1} , \frac{7k + 3}{k + 1} )$

$3( \frac{2k + 1}{k + 1} ) + (\frac{7k + 3}{k + 1} ) - 9 = 0 \\ \\ 3(2k + 1) + (7k + 3) - 9(k + 1) = 0 \\ \\ 6k + 3 + 7k + 3 - 9k - 9 = 0 \\ \\ 4k - 3 = 0 \\ \\ k = \frac{3}{4}$

Ratio = k: 1

= 3/4:1

= 3:4