Question

Determine the the number nearest to 100000 but greater than 100000 which is exacly divisible by each of 8 15 21

Answer 1

Hey there!

First,
Taking the LCM of 8, 15 and 21.

LCM (8, 15, 21) = 840

Now We'll divide 100000 by 840.
We got remainder 40 after division.

So we have to compensate 40.

Now your requirement is the number which is greater than 100000, so you will get it by,

100000+840-40

= 100800 

Hence,
100800 is the required number, which is divisible by 8, 15 and 21.

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Answer 2

Answer:

100800

Step-by-step explanation:

first find lcm of 8 15 21

=840

then divide 100000 by 840 remainder is 40

then subtract 40 from 840

that is 800

then add 100000 and 800

= 100800 ANS