Math, asked by mayanklodha1710, 1 year ago

Determine the the number nearest to 100000 but greater than 100000 which is exacly divisible by each of 8 15 21.

Answers

Answered by supersonu

The LCM of 8 , 15 ,21 is 840
100000 when divided by 840 is 119 with some remainder

So the required number is 840 × 120 which is
100800.

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Answered by Abhirup1

LCM of 8 ,15,21 is 840 . number more than 100000 is 100800.

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