Question

determine which of the following polynomials has(x+1)as a factor

Answer 1

p(x) = x³ - x² - x + 1
=> p(x) = x²(x+1) - 2x (x+1) +1(x+1)
=> p(x) = (x+1)(x²-2x+1)
So, we can see that p(x) has a factor (x+1).

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Answer 2

Answer:

$(x+1)as \: a \: factor \\ x + 1 = 0 \\ x = - 1 \\ {x}^{3} - {x}^{2} - x + 1 = 0 \\ {( - 1)}^{3} - {( - 1)}^{2} - ( - 1) + 1 = 0 \\ - 1 - 1 + 1 + 1 = 0\\ - 2 + 2 = 0 \\ it \: satisfy \: \: ... \\ so \: (x+1)as \: a \: factor$