Question

Dhaka address accelerated uniformly and attains a speed of 72 kilometre per hour in 10 second calculate the acceleration and the distance covered by a car in that time.​

Answer 1

Answer:

Initial velocity ,u = 0

Final velocity, v = 72 km/h = 72× 5/18 = 20m/s

Time ,t = 20 s

So, acceleration ,a = v-u/t = 20-0/10 = 20/10 = 2 m/s^2

Distance travelled = s = ut+1/2at^2

= 0× 10 + 1/2 × 2×10×10

0+ 100

= 100 m.

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