Math, asked by Anonymous, 11 months ago

Differentiate it →  \sf \red{{2}^{x} + }3{x}^{2} + 5x + 1000000

Answers

Answered by Anonymous
31

Question:

Differentiate  \: it  \\   \sf \red{{2}^{x} + }3{x}^{2} + 5x + 100

Answer:

 \implies {2}^{x}  + 3 {x}^{2}  + 5x + 1000000 \\  \\  \: diff.w.r.t.x \\  \\  \implies \:  {2}^{x} log2 + 6x + 5 + 0

{2}^{x }  log2+ 6x + 5

Answered by Anonymous
13

Let

y = 2^x + 3x^2 + 5x + 100000

differentiating with respect to X we get

dy/dx = 2^x*log2+ 6x + 5

So answer is

2^x*log2+ 6x + 5

To know how it is solved

y = 2^x

logy = xlog2

differentiating with respect to

dy/ydx = log2

Dy/dx = y*log2

dy/dx = 2^x log2

differentiation of constant is 0

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