Diagonal of a rectangle is 13 and its perimeter is 34 find area
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Answered by
0
Answer:
60cm*cm
Step-by-step explanation:
Perimeter of rectangle = 2(L+ B) = 34 cm
=> L + B = 17 cm ……. (1)
Since diagonal = 13 cm
By pythagoras law
13² = L² + B²
=> 169 = (L + B)² - 2LB
=> 169 = 17² - 2LB
=> 2LB = 289 - 169 = 120
=> LB = 60
Area = 60 cm²
Answered by
1
perimeter=2(l+b)=34
l+b=17
d=13
by Pythagoras theorem
H^2= P^2+B^2
13^2= (L+B)^2
169=17^2-2LB
169-289=-2LB
120=2LB
LB=60
area of rectangle =LB=60
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