Math, asked by rupalgori217, 8 months ago

Diagonals AC and BD of a quadrilateral ABCD intersect each other at 0.

Prove that: AB + BC + CD + DA > AC + BD

Answers

Answered by khansabairam

7

Step-by-step explanation:

this is your answer.........

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Answered by khansaba04

1

hope it helps you ✔️✔️✔️✔️

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