diagonals of a trapezium ABCD with ABllCD intersect each other at the point O. lf AB=2CD .find ratio of area's of AOB and COD
Answers
Answered by
7
∆AOB and ∆COD
angle AOB= angle COD
angle OAB= angle OCD
angle OBA=angle ODC
hence
∆AOB~∆COD
hence
ar∆AOB/ar∆COD=(AB/CD)^2=(2)^2=4
angle AOB= angle COD
angle OAB= angle OCD
angle OBA=angle ODC
hence
∆AOB~∆COD
hence
ar∆AOB/ar∆COD=(AB/CD)^2=(2)^2=4
Similar questions