Dice thrown twice write the sample space state the probability of getting a doublet also write the favourable outcome
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Step-by-step explanation:
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Step-by-step explanation:
the sample space is denoted by s
s= 1,2,3,4,5,6 in a die there are 6 faces
s= (1,1),(1,2),(1,3),(1,4),(1,5),(1,6)
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5) (3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)
(6,1),(6,2),(6,3),(6,4),6,5,),(6,6)
for favourable outcomes same you can write I hope you would understand
there are 6 doubles so multiply 6×6=36
no .of favourable outcomes =6
total no of outcomes =36
1/6 is your answer
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