Question

Dielectric strength of a medium is 2 kv mm^-1. What is the maximum potential difference that can be set up accros a 50 mm specimen without puncturing it?

Answer 1

The maximum potential difference is 100 v.

Explanation:

As we know that

Dielectric strength = Potential difference gradient.

Hence maximum potential difference = Dielectric strength × distance

= 2000 V / mm × 50μm

= 2000 V / 10^−3 m × 50 × 10^−6 m

= 100 V.

Hence the maximum potential difference is 100 v.

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