Question

difference between two numbers is 4 and the difference between their squares is 80 find the numbers​

Answer 1

Answer:

Let the numbers are x and y,

Since, the sum of squares of two numbers is 80,

⇒ x² + y² = 80 -----(1)

And, the square of difference between the two numbers is 36,

⇒ (x - y)² = 36

⇒ x² + y² - 2 xy = 36

⇒ 80 - 2xy = 36  ( From equation (1) ),

⇒ -2xy = -44

⇒ xy = 22

Thus, the product of the two numbers is 22.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

let the no be = x

= x-(80-x) =4

= 2x+80 = 4

= 2x = 4+80

= 2x = 84

= x = 84÷2 = 41 ( first no. )

= 80-41 = 39 ( second no. )