Question

the kinetic energy of an object of mass M is moving with a velocity of 5 metre per second is 25 jewels calculate its kinetic energy when its velocity is doubled what will be its kinetic energy when its velocity is increased three times​

Answer 1

Answer:

Kinetic energy is

$e = \frac{1}{2} m {v}^{2}$

So it is proportional to square of velocity.

Now

When velocity is doubled , kinetic energy will be 4 times or 25 × 4 = 100 J

&

When velocity is 3 times , kinetic energy will be 9

times or 25 × 9 = 225 J

Answer 2

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ANSWER :

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The mass of the object, m = m kg

The speed of the object, v = 5 m/s

The Kinetic Energy, K.E = 25 J

We know that ,

$kinetic \: energy = \frac{1}{2} mv ^{2}$

From this ,,,

Kinetic Energy ,K.E = 1/2 × m× (5)^2

25 = 1/2 × m × 25

m = 2 kg

(i) Now the Velocity of the object is doubled,,

v2 = 2v1

= 2( 5)

v2 = 10 m/s

Kinetic Energy, K.E = 1/2 × m × (v2)^2

= 1/2 × 2 × 10^2

= 100 J

The Kinetic Energy is 100 J.

(ii) Now the velocity is tripled ,,

v3 = 3v1

= 3 ( 5)

v3 = 15 m/s

Kinetic energy, K.E = 1/2 × m × (v3)^2

= 1/2 × 2 × (15)^2

= 225 J

The kinetic energy is 225 J

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