Question

differential equation dx/dy= k (a-x)​

Answer 1

Answer:

dx/dt = k(a-x)

(b-x) x(0)=0

The Attempt at a Solution

dx/((a-x)(b-x)) = kdt

Integral (dx/(ab-bx-ax+x^2)) = kt +C x/ab - (1/b)ln|x| - (1/a)ln|x| - (x^-1) = kt + C however, if i try to substitute x(0) = 0, i get the ln 0