Question

differentiate 4x^2+2x^3+5/X+9

​

Answer 1

Step-by-step explanation:

ANSWER

dx

dy

=

dx

d

[4x

4

+2x

3

+

x

5

+9]

(Differentiating both sides w.r.t. x)

=

dx

d

[4x

4

]+

dx

d

[2x

3

]+

dx

d

[

x

5

]+

dx

d(9)

(Using the property of linearity)

=

dx

d

[4x

4

]+

dx

d

[2x

3

]+

dx

d

[

x

5

]

(As differentiation of constant =0,

dx

d9

=0)

=4

dx

d

,[x]

4

+2

dx

d

[x

3

]+5

dx

d

[x

−1

] (Separating constant coefficients)

=4×4x

3

+2×3x

2

+5(−1)x

−2

=16x

3

+6x

2

−

x

2

5

.