differentiate cosec x w.r.t. 'x' by first principle
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y = cosecx
we know ,
Lim(∆x→0)∆y/∆x =Lim(∆x→0){f(x+∆x)-f(x)}/∆x
Lim(∆x→0){cosec(x+∆x)-cosecx}/∆x
use L—Hispital rule ,
dy/dx =-cosecx.cotx
we know ,
Lim(∆x→0)∆y/∆x =Lim(∆x→0){f(x+∆x)-f(x)}/∆x
Lim(∆x→0){cosec(x+∆x)-cosecx}/∆x
use L—Hispital rule ,
dy/dx =-cosecx.cotx
Anonymous:
using lim
what ?
you means limit is 1st principal
lim{ f(x+h) - f(x) }/ h where h tends to zero...this is the method to proof..by 1st principle
solve this question by rhis
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hope it will help.....
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