Differentiate e^x from first principle
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Step-by-step explanation:
f(x) = e^x,so, f(x+h) = e^(x+h) , hence , differentiating by first principle we can write,
f'(x) = Lt h=>0 { f(x+h) - f(x)}/h
=> Lt h=>0 { e^(x+h) - e^x}/h
=> e^x[ Lt h=>0 {e^h - 1}/h]
= e^x *1
= e^x
** As we know Lt h=> 0 {e^h - 1}/h = 1
nahendramadineni:
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