Differentiate log(sec²x/2)
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log(sec^2x/2)=log(sec^2x)-log(2)
now log(sec^2x) can be written as 2×log(sec x)
differentiate it you get 2×(1/sec x)×d(sec x)-0
=2×(1/sec x)×(sec x×tan x)=2×tan x.
Hence the ans of you question is "2×tan x"
now log(sec^2x) can be written as 2×log(sec x)
differentiate it you get 2×(1/sec x)×d(sec x)-0
=2×(1/sec x)×(sec x×tan x)=2×tan x.
Hence the ans of you question is "2×tan x"
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