Differentiate sinx.cosx w.r.tx
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Now if I differentiate both sides of the equation with respect to x (because both are equal, their derivatives should also be equal), I will have cos x = 0, right? ... Since x = π/6, both "x" and "sin(x)" are constants (because sin(π/6) = 1/2) and the derivative of a constant is zero.
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Proving that the derivative of sin(x) is cos(x) and that the derivative of cos(x) is -sin(x).
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