Differentiate the given
(or just gimme first 2 - 3 steps )
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Step-by-step explanation:
let u=sinx, x=sin inv(u)
so u/√1-u²=sinx/cox=tanx
tan inv(tanx)=x=sin inv u
y= tan inv (u/√1-u²)=sin inv u
so dy/du=d/du[ tan inv (u/√1-u²)]
=d/du[sin inv(u)]
= 1/√(1-u²)
I hope this will help ,If any any problem please write in comments
mudit11:
thanks.
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