liquid enters a tube of variable cross section with a velocity 3 m/s through the wider end and leaves from the narrower end whose radius is half of that wider one the velocity with which it leaves the tube is
Answers
we know that the amount of water that enters will come out it will not be increased or decreased
so according to the law of continuity
A(area) × V(velocity) will be constant
we can say
water entering =water exiting
area of broader end × velocity of water in broader end = area of smaller end × velocity of water in narrow end
pie
where {ve} is the velocity of water entering
and {vi} is the velocity leaving
after putting the values and calculations
we get
{vi} = 12 m/s
we know that the amount of water that enters will come out it will not be increased or decreased
so according to the law of continuity
A(area) × V(velocity) will be constant
we can say
water entering =water exiting
area of broader end × velocity of water in broader end = area of smaller end × velocity of water in narrow end
π
where {ve} is the velocity of water entering
and {vi} is the velocity leaving
after putting the values and calculations
we get
= 12 m/s