Physics, asked by nsravni180, 1 year ago

liquid enters a tube of variable cross section with a velocity 3 m/s through the wider end and leaves from the narrower end whose radius is half of that wider one the velocity with which it leaves the tube is

Answers

Answered by Happypincha111
9

we know that the amount of water that enters will come out it will not be increased or decreased

so according to the law of continuity

A(area) × V(velocity) will be constant

we can say

water entering =water exiting

area of broader end × velocity of water in broader end = area of smaller end × velocity of water in narrow end

pie

{ve} \times \pi \:  {r}^{2}  = \pi {r \div 2}^{2}  \times {vi}

where {ve} is the velocity of water entering

and {vi} is the velocity leaving

after putting the values and calculations

we get

{vi} = 12 m/s


nsravni180: Thank you
Happypincha111: welcome dear
Answered by leobhavan10
1

we know that the amount of water that enters will come out it will not be increased or decreased

so according to the law of continuity

A(area) × V(velocity) will be constant

we can say

water entering =water exiting

area of broader end × velocity of water in broader end = area of smaller end × velocity of water in narrow end

π

where {ve} is the velocity of water entering

and {vi} is the velocity leaving

after putting the values and calculations

we get

= 12 m/s

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