Question

Differentiation of:ex(x+ log x)

Answer 1

Answer:

Step-by-step explanation:

Differentiation of e^(x*logx) is  (1 + logx)e^(x*logx).

Following chain rule,

Differentiating e^(x*logx) gives e^(x*logx) (bcos d/dx (e^x)=e^x )

then differentiating x*logx gives (1 + logx)

(bcos d/dx(x*log) = x * d/dx(logx) + logx * d/dx(x)   (product rule)

                             = x * 1/x + logx * 1

                             = 1 + logx    ).

Answer 2

Answer:

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