Question

differentiation of (t-2/2t+1)^9​

Answer 1

Answer:

Y = (t-2/2t+1)^9

Take Log on both sides

ln Y = 9 ln (t-2/2t+1)

differentiating both sides ;

1/Y . dY/dt = 9.(2t+1/t-2). [(2t+1) - (t-2).2]/2t+1

now you can find the answer