diffrenciate sin inverse[a+bcosx/b+acosx]
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sin inverse [a+bcosx/b+acosx]
=1/√1_[a+bcosx/b+acosx] whole square d/dx[a+bcosx/b+acosx]
=1/√1_[a+bcosx/b+acosx]whole square (_bsinx/b_asinx)
=1/√1_[a+bcosx/b+acosx] whole square d/dx[a+bcosx/b+acosx]
=1/√1_[a+bcosx/b+acosx]whole square (_bsinx/b_asinx)
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