Question

Dihydrogen reacts with dioxygen ($O_{2}$) to form water. Write the name and formula of the product when the isotope of hydrogen which has one proton and one neutron in its nucleus is treated with oxygen. Will the reactivity of both the isotopes be the same towards oxygen? Justify your answer.

Answer 1

The hydrogen isotope consists one “neutron” and one “proton” called Deuterium. The Deuterium reacts with dioxygen to form deuterium oxide.

Deuterium oxide is called “heavy water” and the reaction is as follows.

$\begin{matrix} 2{ D }_{ 2(g) } \\ Dudeuterium \end{matrix}\quad +\quad \begin{matrix} { O }_{ 2(g) } \\ Dioxygen \end{matrix}\quad \xrightarrow { Heat } \quad \begin{matrix} 2{ D }_{ 2 }O \\ Deuterium\quad oxide \end{matrix}$

The reactivity of ${ O }_{ 2 }$ and  ${ D }_{ 2 }$ is different towards oxygen because H-H bond weaker than D-D bond.

Therefore, ${ H}_{ 2 }$ is more reactive than ${ D }_{ 2 }$ towards reaction with oxygen.

Answer 2

Answer:2H2 +o2------->2h2o

Explanation:dihydrohen with dioxygen to give water (h2o)