dilute hydrochloric acid is added to solid sodium carbonate
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Answered by
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HCl + NaCO3 → NaCl2 + CO2 + H2O
Answered by
1
When we add Dill. HCl with Na2CO3.
Then the resultant products will be:-
Na2CO3+HCl---2NaCl+H2O+CO2.
Or
Na2CO3+HCl---2NaCl+H2CO3
Then the resultant products will be:-
Na2CO3+HCl---2NaCl+H2O+CO2.
Or
Na2CO3+HCl---2NaCl+H2CO3
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