Question

dimension of magnetic field intensity (B)

Answer 1

MT-2L-1 is the dimension of magnetic field intensity B

Answer 2

Answer:

The dimension of magnetic field intensity B = $\rm [M^1L^0T^{-2}A^{-1}].$  

Explanation:

The dimension of magnetic field intensity B can be found as follows:

We know, the magnitude of the force acting on a charged particle moving inside a magnetic field is given by

$\rm F=qvB\\\Rightarrow B= \dfrac{F}{qv}.$

where,

• F = magnetic force on the charged particle.

• v = velocity of the charged particle.

• B = magnetic field intensity.

• q = amount of charge on charged particle.

The dimesnions of following quantities are:

$\rm F = [M^1L^1T^{-2}]\\v =[M^0L^1T^{-1}]\\q =[M^0L^0T^1A^1]\\\\Thus, \\Dimension\ of\ B = \dfrac{[M^1L^1T^{-2}]}{[M^0L^1T^{-1}][M^0L^0T^1A^1]}=\dfrac{[M^1L^1T^{-2}]}{[M^0L^1T^0A^1]}=[M^1L^0T^{-2}A^{-1}].$