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Solution :-
Diameter of the capsule = 5 mm
Radius of the capsule = 5/2 mm
Radius of the capsule = Radius of the cylindrical part = Radius of the hemispherical part.
Length of the cylindrical part = Length of entire capsule - Length of two hemispherical parts
⇒ 14 mm - (2.5 mm + 2.5 mm)
⇒ 14 mm - 5 mm
= 9 mm
Total surface area of entire capsule = Surface area of the cylindrical part + Surface area of two hemispherical parts
⇒ 2πrh + 2*(2πr²)
⇒ 2*22/7*5/2*9 + 4*22/7*5/2*5/2
⇒ 1980/14 + 2200/28
⇒ 141.4285 + 78.5714
= 219.9999 mm²
or 220 mm (Approximately)
So, the surface area of entire capsule is 220 mm²
Answer.
Diameter of the capsule = 5 mm
Radius of the capsule = 5/2 mm
Radius of the capsule = Radius of the cylindrical part = Radius of the hemispherical part.
Length of the cylindrical part = Length of entire capsule - Length of two hemispherical parts
⇒ 14 mm - (2.5 mm + 2.5 mm)
⇒ 14 mm - 5 mm
= 9 mm
Total surface area of entire capsule = Surface area of the cylindrical part + Surface area of two hemispherical parts
⇒ 2πrh + 2*(2πr²)
⇒ 2*22/7*5/2*9 + 4*22/7*5/2*5/2
⇒ 1980/14 + 2200/28
⇒ 141.4285 + 78.5714
= 219.9999 mm²
or 220 mm (Approximately)
So, the surface area of entire capsule is 220 mm²
Answer.
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