Biology, asked by amoeba44, 1 year ago

Direct ATP yield of aerobic respiration during krebs cycle per glucose molecule is
a]2ATP molecules
b]8ATP molecules
c]36 ATP molecules
d] 38ATP molecules

Answers

Answered by vishwapatel18111
4
\huge{a] 2ATP Molecules}

\huge{Please  mark my  answer  as  brainliest.}

amoeba44: yes...but how?
vishwapatel18111: I think, In aerobic conditions, the process converts one molecule of glucose into two molecules of pyruvate (pyruvic acid), generating energy in the form of two net molecules of ATP. Fourmolecules of ATP per glucose are actually produced, however, two are consumed as part of the preparatory phase.
vishwapatel18111: Please mark my answer as brainliest
amoeba44: thankyouu
vishwapatel18111: welcome!
Answered by Anonymous
6

i think your answer ❤❤♥♥♥♥❤❤❤♥♠♣❤❤. oneNADH = 3 molecules of ATP.Hence the indirect gain is 2×3=6ATP TOTAL GAIN OF ATP = 2+6= 8ATP . In cells which use oxygen, the pyruvate is used in a second process, the Krebs cycle, which produces more ATP molecules. please mark as s brilliant


amoeba44: actually the answer is a but i dont know how....
Prinaka: After glycolysis the answer can be 2 ATP molecules but after Krebs cycle, the terminal oxidation is already finished so 38 ATP Energy is released.
amoeba44: yes but this is during krebs cycle
Prinaka: So the answer should be (d) 38 ATP
amoeba44: but krebs cycle is not complete na
Prinaka: Then it is 2 ATP
Anonymous: hi
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