Direct ATP yield of aerobic respiration during krebs cycle per glucose molecule is
a]2ATP molecules
b]8ATP molecules
c]36 ATP molecules
d] 38ATP molecules
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Answered by
4
amoeba44:
yes...but how?
Answered by
6
i think your answer ❤❤♥♥♥♥❤❤❤♥♠♣❤❤. oneNADH = 3 molecules of ATP.Hence the indirect gain is 2×3=6ATP TOTAL GAIN OF ATP = 2+6= 8ATP . In cells which use oxygen, the pyruvate is used in a second process, the Krebs cycle, which produces more ATP molecules. please mark as s brilliant
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