Question

Distance of object and its image from optical centre of lens are 10 cm and 30 cm respectively the ratio of height of image and object

Answer 1

Answer:

it's answer will be 40

Explanation:

30+10=40

Answer 2

Answer:

The ratio of the height of the image and object is 3:1.

Explanation:

Given:

Distance of object (u) = 10cm

Distance of image (v) = 30cm

To find:

Ratio of heights of image and object $(\frac{h_1}{h_2})$

Solution:

We know that magnification is given as $m=\frac{h_1}{h_2}$ and $m = \frac{v}{u}$.

Combining the two formulas, we get

$\frac{h_1}{h_2} = \frac{v}{u}$

Substituting the given values of v and u.

$\frac{h_1}{h_2} = \frac{30}{10}$

$\frac{h_1}{h_2} = \frac{3}{1}$

Therefore, the ratio of heights of image and object for the given lens is 3:1

#SPJ3