Question

distance of the point whose ordinate is 3 and abscissa is 7 from the point (-1,4) is ​

Answer 1

Answer:

answer is 5 cm

Step-by-step explanation:

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Answer 2

The distance of the point whose ordinate is 3 and abscissa is 7 from the point (-1,4) is $\sqrt{65}$ units.

Explanation:

Distance formula : The distance between two points (a,b) and (c,d) is given by :-

$D=\sqrt{(c-a)^2+(d-b)^2}$

The coordinate for point with ordinate is 3 and abscissa is 7 = (7, 3)

Then, the distance between (7,3) and the point (-1,4) would be

​$D=\sqrt{(-1-7)^2+(4-3)^2}$

​$D=\sqrt{(-8)^2+(1)^2}$

​$D=\sqrt{64+1}=\sqrt{65}$ units.

Hence, the distance of the point whose ordinate is 3 and abscissa is 7 from the point (-1,4) is $\sqrt{65}$ units.

#Learn more :

Find the ordinate of a point whose abscissa is 10 and which is at a distance of 10 units from the point P(2,-3).

https://brainly.in/question/8903