Distribute 60 choclates in 3 persons A,B,C such that A gets more than B and B gets more than C. In how many different ways this can be done
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A can get 30 chocolate. B can get 20 chocolate and C can get 10 chocolate .
See their are so many combination in which it can done.
please mark as brainliest if you like so
See their are so many combination in which it can done.
please mark as brainliest if you like so
Answered by
0
Let the number of choclatesfor A,B,C be x,y,z
x+y+z=60
number of ways it can be distributed=3^2=3*3=9
x+y+z=60
number of ways it can be distributed=3^2=3*3=9
oblivion:
wrong answer :)
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