divert the formula of kinetic energy
Answers
Suppose, the mass of a moving object = m
The initial velocity of a moving object = u
The acceleration of the object = a
The final velocity of the object = v
Displacement of object to achieve the final velocity = s.
We know from the equation of motion that,
v2=u2+2asv2=u2+2as
⇒2as=v2−u2⇒2as=v2-u2
⇒s=v2−u22a⇒s=v2-u22a -----(i)
Now, we know that, Work done, W=F×sW=F×s
Thus, by substituting the value of ‘s’ from equation (i) in the expression W = F x s, we get
W=F×v2−u22aW=F×v2-u22a
Now, according to Newton’s Second Law of motion, Force = mass x acceleration
Or, F = m x a
Therefore, by substituting the value of F in equation (ii) we get,
W=m×a×v2−u22aW=m×a×v2-u22a
⇒W=12m(v2−u2)⇒W=12m(v2-u2) ---(iii)
If the object starts moving from the state of rest, therefore, initial velocity (u) will be equal to zero.
Therefore, equation (iii) can be written as
⇒W=12m(v2−02)⇒W=12m(v2-02)
⇒W=12mv2⇒W=12mv2 ------(iv)
Equation (iv) shows that work done is equal to the change in kinetic energy of an object.
Therefore, if an object of mass ‘m’ is moving with a constant velocity,
Thus, the Kinetic Energy (Ek)=12mv2(Ek)=12mv2 ----(v)