Question

Divide 150 into three parts such that the second number is fifth- sixths the first number and the third number is four fifths the second

Answer 1

assume three no are x,y,z then x+y+z=150 and x=(5÷6)y and y=(4÷5)z there for x=(2÷3)z and (2÷3)z+(4÷5)z+z=150 z =60.81. x=(2÷3)z=40.54. y=(4÷5)z=48.64