Question

divide

(16pr² - 8pr³- 4p²r5)

by -4pr²​

Answer 1

Answer:

hope it's help you plese mark me as brainlist

Answer 2

Answer:

$\frac{16pr^2 - 8pr^3 - 4p^2r^5}{-4pr^2}$  $=(pr^3 + 2r - 4)$

Step-by-step explanation:

$16pr^2 - 8pr^3 - 4p^2r^5$

$=-4pr^2(-4 + 2r + pr^3)$

$=-4pr^2(pr^3 + 2r - 4)$

∴ $\frac{16pr^2 - 8pr^3 - 4p^2r^5}{-4pr^2}$ $= \frac{-4pr^2(pr^3 + 2r - 4)}{-4pr^2}$ $=(pr^3 + 2r - 4)$