Divide 184 into two parts such that 1/3rd of one part may exceed 1/7th of another part by 8
Answers
Answered by
8
Let 1 part is x. So another part will be (184-x).
According to question
(x/3)-((184-x)/7)=8
7x- 3*(184-x) = 8*21
7x - 552 + 3x = 168
10x = 720
Therefore, x=72 (1st part)
So, 184-x = 112 (2nd part)
According to question
(x/3)-((184-x)/7)=8
7x- 3*(184-x) = 8*21
7x - 552 + 3x = 168
10x = 720
Therefore, x=72 (1st part)
So, 184-x = 112 (2nd part)
Answered by
1
X+y=184
X=184-y
X/3=(y+8)/7
7x=3y+24
7(184-y)=3y+24
1288-7y=3y+24
7y+3y=1288-24
10y=1264
Y=126.4
X=184-126.4
X=57.6
The two parts are 57.6 and 126.4
X=184-y
X/3=(y+8)/7
7x=3y+24
7(184-y)=3y+24
1288-7y=3y+24
7y+3y=1288-24
10y=1264
Y=126.4
X=184-126.4
X=57.6
The two parts are 57.6 and 126.4
Similar questions
Social Sciences,
1 year ago
Computer Science,
1 year ago