Math, asked by pkvortex08, 1 year ago

Divide 184 into two parts such that 1/3rd of one part may exceed 1/7th of another part by 8

Answers

Answered by cool30sanjuoyfoyu
8
Let 1 part is x. So another part will be (184-x).
According to question
(x/3)-((184-x)/7)=8
7x- 3*(184-x) = 8*21
7x - 552 + 3x = 168
10x = 720
Therefore, x=72 (1st part)
So, 184-x = 112 (2nd part)
Answered by shrutishelar
1
X+y=184
X=184-y

X/3=(y+8)/7

7x=3y+24
7(184-y)=3y+24
1288-7y=3y+24
7y+3y=1288-24
10y=1264
Y=126.4

X=184-126.4
X=57.6

The two parts are 57.6 and 126.4
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