Question

divide 184 into two parts such that one third of one part may exceed 17 of the Other Part by eighti

Answer 1

Let 184 = x + y
Given, x/3 = y/7 + 8
184 = x + y
184 -y = x
Then,
x/3 = y/7 + 8
184/3 - y/3 = y/7 + 8
Multiply both side wit 21 because l.c.n of 3 and 7.
21 (184/3) - 21 (y/3) = 21 (y/7) + 21 (8)
1288 - 7y = 3y + 168
-3y - 7y = -1288 + 168
-10y = -1120
y = -1120/-10
y = 112
x = 184 - y
= 184 - 112
= 72
.°., the numbers are 72 and 112.