Question

divide 234 into 3 parts such that half of the first part one third of the second part and one fourth of the third part equal​

Answer 1

Step-by-step explanation:

let

the each parts of the number be X

given:-

$the \: first \: part \: of \: number = \frac{x}{2} \\ the \: second \: part \: of \: number = \frac{x}{3} \\ the \: third \: part \: of \: number = \frac{x}{4} \\ now \: according \: to \: question \\ = > \frac{x}{2} + \frac{x}{3} + \frac{x}{4} = 234 \\ = > \frac{6x + 4x + 3x}{12} = 234 \\ = > \frac{13x}{12} = 234 \\ = > 13x = 234 \times 12 \\ = > x = \frac{234 \times 12}{13} = 216 \\ first \: part = \frac{x}{2} = \frac{216}{2} = 108 \\ second \: part = \frac{x}{3} = \frac{216}{3} = 72 \\ third \: part = \frac{x}{4} = \frac{216}{4} = 54$

hence:-

the three parts are 108 , 72 and 54