Question

divide 24 in three parts such that they are in AP and their product is 440​

Answer 1

Answer:

Let the three parts be a, a+d , :-!

a + a+d + a-d= 24

3a=24

a=24/3

a=8

a x a+d x a-x= 440

a x a2 - d2 =440

8 x 64 -d2=440

512 - d2=440

512-440 = d2

72=d2

d= square root of 72

a=8

a+d= 8 + square root of 72

a-d= 8 - square root of 72

Answer 2

let the three parts be a-d , a, a+d

ATQ

a - d + a + a + d = 24

3a = 24

a = 8

(a-d)(a)(a+d) = 440

(a² - ad)(a+d) = 440

a³ + a²d - a²d - ad² = 440

a³ - ad² = 440

8³ - 8d² = 440

-8d² = 440 - 512

-8d² = -72

d² = 9

d = √9

d = 3

So the three numbers will be

a - d = 5

a = 8

a + d = 11

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