divide 2x^3+x^2+3x by 2x
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(2x^3+x^2 +3x)/2x
= ( 2x^3/2x)+ (x^2/2x) + (3x/2x)
= x^2 + (x/2) +(3/2)
= ( 2x^3/2x)+ (x^2/2x) + (3x/2x)
= x^2 + (x/2) +(3/2)
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