Math, asked by sachinguptasalini, 3 months ago

- Divide 396 among X, Y and Z in the
ratio 4:5:9.
Dotermine whether the following ratios​

Answers

Answered by sarvadarshita
1

Step-by-step explanation:

let the common number be a

X = 4a

Y = 5a

Z = 9a

4a + 5a + 9a = 396

= 18a = 396

= a = 396\18

= a = 22

X = 4a = 4×22 = 88

Y = 5a = 5×22 = 110

Z = 9a = 9×22 = 198

Answered by Eutuxia
14

Before, finding the answer. Let's find out on how we can find the answer.

  • First, we must add up all the ratios.
  • Then, we must divide the total ratio with the total number.
  • At last, we must multiply the given numbers with the divided numbers.

____________________

Given :

  • Total Number = 396
  • Ratio = 4:5:9

To find :

  • how much each will get if divided

Solution :

Let x be a common multiple in the given ratio.

Total Ratio = 4x : 5x : 9x

= 4 + 5 + 9

= 18

 \sf 1  \: part =  \dfrac{total \: number}{total \: ratio}

 \sf  =  \dfrac{396}{18}

 \sf = 22

Hence, One part is 22.

----------

One part = x

4x = 4 × x

= 22 × 4

= 88

5y = 5 × x

= 22 × 5

= 110

9z = 9 × x

= 22 × 9

= 198

Hence,

4x = 88

5x = 110

9x = 198

-----------

Verification :

Total Ratio = 396

396 = X + Y + Z

396 = 88 + 110 + 198

396 = 396

Hence, L.H.S = R.H.S

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