Divide 4864 into three parts such that the second part is five times the first and the ratio of the second part to the third part is 3:4
Answers
Answered by
10
Second part = 3x
Third part = 4x
Second part = 5 first part
3x = 5 first part
First part = 3x/5
1st part + 2nd part + 3rd part = 4864
3x/5 + 3x + 4x = 4864
3x + 15x + 20x = 4864*5
38x = 24320
X = 640
1st part = 3x/5 = (3*640)/5 = 384
2nd part = 3x = 3*640 = 1920
3rd part = 4x = 4*640 = 2560
Answered by
9
We will consider three numbers x,y & z such that there sum is 4864
so,
x+y+z=4864 ..................(i)
ATQ,
y=5x
=> x=y/4
and
y/z=3/4
=>z=4y/3 (cross multiplying)
Substituting the values of x , z in equation 1
=>y/4 + y + 4y/3=4864
(
Taking LCM i.e. 15 )
=> (3y+15y+20y)/15=4864
=>solving the equation gives;
y=1920,
Thus
x= y/5=1920/5=384
z=4y/3=4(1920)/3=2560
Thus three numbers are
384,1920,2560
THATS ALL FOLKS !!!
so,
x+y+z=4864 ..................(i)
ATQ,
y=5x
=> x=y/4
and
y/z=3/4
=>z=4y/3 (cross multiplying)
Substituting the values of x , z in equation 1
=>y/4 + y + 4y/3=4864
(
Taking LCM i.e. 15 )
=> (3y+15y+20y)/15=4864
=>solving the equation gives;
y=1920,
Thus
x= y/5=1920/5=384
z=4y/3=4(1920)/3=2560
Thus three numbers are
384,1920,2560
THATS ALL FOLKS !!!
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