Math, asked by Raajkumar9451, 1 year ago

Divide 534 into three parts such that the second part will be 32 less than twice of the first and the third will be 18 more than the first

Answers

Answered by anubhtha
0
first part 137
second part 242
third part 155
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Answered by KrishnaBirla
1
Please \: Mark \: Me \: As \: BRAINLIEST. \\ .................................................. \\ Also \: Don't \: Forgot \: to \: Follow \: me. \\ .............. \\ As \: we \: know \: about \: Equations. \\ So, \\ Hello \: Guys, \\ ................ \\ Answer \: is
Let \: first \: no. \: be \: x. \\ \: \: \: \: Second \: no. = 2 \times x - 32 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2x - 32 \\ \: \: \: \: \: \: \: Third \: no. = x + 18 \\ ATQ, \\ x + 2x - 32 + x + 18 = 534 \\ 4x - 14 = 534 \\ 4x = 534 + 14 \\ 4x = 548 \\ x = \frac{548}{4} \\ x = 137 \\ \\ First \: no. = 137 \\ Second \: no. = 137 \times 2 - 32 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 274 - 32 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 242 \\ Third \: no. = 137 + 18 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 155
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