Divide 57 into two parts whose product is 680
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Answered by
4
x(57-x)=680
57x-x²=680
x²-57x+680=0
x²-40x-17x+680=0
x(x-40)-17(x-40)=0
(x-17)(x-40)=0
x=17,40
57x-x²=680
x²-57x+680=0
x²-40x-17x+680=0
x(x-40)-17(x-40)=0
(x-17)(x-40)=0
x=17,40
Answered by
1
hey dear
first part = x
second= 57-x
x(57-x)=680
57x-x^2=680
x^2-57x+680=0
by solving this we get
x = 17 or 40
so numbers are 17 and 40
first part = x
second= 57-x
x(57-x)=680
57x-x^2=680
x^2-57x+680=0
by solving this we get
x = 17 or 40
so numbers are 17 and 40
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