Question

divide 60 into two parts, such that 3 times the smaller part may exceed 100 by as much as 9 times bigger falls short of 200.

Answer 1

Solution:-
Let the one part be 'x'
Then the other part will be 60 - x
So, according to the question.
3(60 - x) - 100 = 200 - 9(x)
180 - 3x - 100 = 200 - 9x
- 3x =9x = 200 + 100 - 180
6x = 120
x = 120/6 
x = 20 
Then the other part is 60 - 20 = 40
Answer.

Answer 2

let 'x'
other 60-x
ACC. to question
3(60-x)-100=200-9(X)
180-3x-100=200-9x
-3x=9x=200+109-180
6x=120
X=120/6
X=20
other one=60-20
=40