Divide 600 biscuits among 5 boys so that their share are in A.P and the two smallest shares together make one-seventh of what the other three boys get.
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Answered by
5
Answer:
75 Biscuits
Step-by-step explanation:
5a=600
a=120
2a- 3d= 1/7(3a+3d)
2(120) - 3d= 1/7(3(120) +3d)
1680 - 21d = 360 + 3d
d=55
Hence Shares are 10, 65, 120, 175 and 230
SO sum is 75
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