Question

Divide 600 in two parts such that 40% of one exceeds 60% of the other by 120.

Answer 1

Let the one part = x
then the other part = 600 - x

Now, according to the question..

  (x × 40)/100 = {(600 - x) × 60}/100 + 120

solving it we get......

2x/5 = {(600 - x)3}/5 + 120
2x/5 = (1800 - 3x)/5 + 120 

solving it, we get...
2x/5 = (1800 - 3x + 600)/5
2x + 3x = 1800 + 600
5x = 2400
x = 2400/5
x = 480 
Therefore the first part is 480 and
the other is 600 - 480 = 120

Answer 2

Answer:

480 and 120

Step-by-step explanation:

Solution:-

Let the one part be 'x' and the other part be 600 - x

Therefore, according to the question.

(x × 40)/100 = {(600 - x) × 60}/100 + 120

On solving both L.H.S. and R.H.S. we get

2x/5 = {(600 - x)3}/5 + 120

2x/5 = (1800 - 3x)/5 + 120 

Taking L.C.M of (1800 - 3x)/5 + 120/1, and solving it, we get

2x/5 = (1800 - 3x + 600)/5

2x + 3x = 1800 + 600

5x = 2400

x = 2400/5

x = 480 

second part = 600-480

= 120