Question

Divide 64 into 2 parts such that three times the greater part will be equal to 5 times the smaller one

Answer 1

let the greater part be x and smaller part be (64-x)

3x=5(64-x)

3x=320-5x

8x=320

x=40

so 64-x= 64-40= 24

so the two parts are 40 and 24

Answer 2

let the no.{64} be divided into a and b

a>b

according tt he given condition

3 a = 5b

a\b = 5\3 =>a=5b\3

but a+b=64

since a=5b\24

thus

5b\24 = b =64

29b\24 = 64

aoing some basic algebraic operations

b= 52.9

thus a=64-52.9

a=11.1