Question

Divide 72 into two parts so that the the largest part exceed the smaller part by 12 .find both the parts

Answer 1

If one part is x then other part will be x+12

Their sum = 72
x+x+12=72
2x+12=72
2x+12-12=72-12
2x=60
/2
2x/2 = 60/2
x=30
One part is 30 so the balance is 42 the other part

Answer 2

Heya..
Here is your answer --

Let the first part be x
Let the second part be x+12
ATQ
x+x+12 = 72
2x+12 = 72
2x = 72-12
2x = 60
x = 60/2
x = 30

First part = x = 30
Second part = x+12 = 30+12 = 42
42+30 = 72

HOPE IT HELPS...!!