Divide 72 into two parts so that the the largest part exceed the smaller part by 12 .find both the parts
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Answered by
1
Let one number be x and other will be x + 12.
Given, x + (x + 12) = 72
2x + 12 = 72
2x = 60
x = 30.
The other number will be x + 12 = 30 + 12 = 42.
Both the parts are 30 and 42.
Hope this helps!
Given, x + (x + 12) = 72
2x + 12 = 72
2x = 60
x = 30.
The other number will be x + 12 = 30 + 12 = 42.
Both the parts are 30 and 42.
Hope this helps!
Answered by
1
Hi ,
Let the smallest part = x
largest part = x + 12
according to the problem given ,
x + x + 12 = 72
2x = 72 - 12
2x = 60
x = 60/2
x = 30
Therefore ,
smaller part = x = 30
larger part = x + 12 = 30 + 12 = 42
I hope this helps you.
:)
Let the smallest part = x
largest part = x + 12
according to the problem given ,
x + x + 12 = 72
2x = 72 - 12
2x = 60
x = 60/2
x = 30
Therefore ,
smaller part = x = 30
larger part = x + 12 = 30 + 12 = 42
I hope this helps you.
:)
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